(w+4)(2w+4)=2w^2+12

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Solution for (w+4)(2w+4)=2w^2+12 equation: 


Simplifying
(w + 4)(2w + 4) = 2w2 + 12

Reorder the terms:
(4 + w)(2w + 4) = 2w2 + 12

Reorder the terms:
(4 + w)(4 + 2w) = 2w2 + 12

Multiply (4 + w) * (4 + 2w)
(4(4 + 2w) + w(4 + 2w)) = 2w2 + 12
((4 * 4 + 2w * 4) + w(4 + 2w)) = 2w2 + 12
((16 + 8w) + w(4 + 2w)) = 2w2 + 12
(16 + 8w + (4 * w + 2w * w)) = 2w2 + 12
(16 + 8w + (4w + 2w2)) = 2w2 + 12

Combine like terms: 8w + 4w = 12w
(16 + 12w + 2w2) = 2w2 + 12

Reorder the terms:
16 + 12w + 2w2 = 12 + 2w2

Add '-2w2' to each side of the equation.
16 + 12w + 2w2 + -2w2 = 12 + 2w2 + -2w2

Combine like terms: 2w2 + -2w2 = 0
16 + 12w + 0 = 12 + 2w2 + -2w2
16 + 12w = 12 + 2w2 + -2w2

Combine like terms: 2w2 + -2w2 = 0
16 + 12w = 12 + 0
16 + 12w = 12

Solving
16 + 12w = 12

Solving for variable 'w'.

Move all terms containing w to the left, all other terms to the right.

Add '-16' to each side of the equation.
16 + -16 + 12w = 12 + -16

Combine like terms: 16 + -16 = 0
0 + 12w = 12 + -16
12w = 12 + -16

Combine like terms: 12 + -16 = -4
12w = -4

Divide each side by '12'.
w = -0.3333333333

Simplifying
w = -0.3333333333

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